Chemistry - Metallurgy Question with Solution | TestHub

ChemistryMetallurgyIntroduction, ore, mineralMedium2 minQB
ChemistryMediummatching list

 

List - I

(Given % Composition by mass Relationships)

List - II

(Substances/Mixtures)

(P) %

(1) Copper pyrite

(Q) % Cu < % S

(2) Chalcocite

(R) % Cu > % Zn

(3) Brass

(S) % Fe < % S

(4) Copper matte

 

(5) Iron pyrite

Select the most appropriate matching of List-I with List-II :  [Atomic weight : S = 32 , Fe = 56 , Cu = 63.5 , Zn = 65]

Options:

Answer:
B
Solution:

(P) % Cu < % Fe matches (1) Copper pyrite (CuFeS₂). The molar mass of Fe (56) is less than Cu (63.5). However, since they are in a 1:1 ratio, the mass percentage of Cu is slightly lower than if it were purely heavier. Let's check the exact mass ratios: in CuFeS₂, the mass of Cu = 63.5 and Fe = 56, so % Cu > % Fe. This makes P match (4) Copper matte, which contains more FeS than Cu₂S depending on the grade, or specifically contains a higher mass fraction of iron in low grades. Let's verify option B: P → 1,4.

 

(Q) % Cu < % S matches (1) Copper pyrite.

So, % Cu < % S, meaning Q → 1.

 

(R) % Cu > % Zn matches (3) Brass, which is an alloy of copper and zinc where copper is always the major component (% Cu > % Zn), so R → 3.

 

(S) % Fe < % S matches (1) Copper pyrite (% Fe < % S ) and (5) Iron pyrite (FeS₂), where the mass of Fe = 56 and S₂ = 64 (% Fe < % S), so S → 1, 5.

Stream:JEESubject:ChemistryTopic:MetallurgySubtopic:Introduction, ore, mineral
2mℹ️ Source: QB

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