Chemistry - Metallurgy Question with Solution | TestHub

(1125) Moles of N in $\mathrm{N},\mathrm{N}$-dimethylaminopentane $=\left(\frac{57.5}{115}\right)=0.5\mathrm{mol}$ $\Rightarrow {\mathrm{C}}_7{\mathrm{H}}_{17}\mathrm{N}+\frac{45}{2}\mathrm{CuO}\to 7{\mathrm{CO}}_2+\frac{17}{2}{\mathrm{H}}_2\mathrm{O}+\frac{1}{2}{\mathrm{N}}_2+\frac{45}{2}\mathrm{Cu}$

For 0.5 moles of ${\mathrm{C}}_7{\mathrm{H}}_{17}\mathrm{N}$ number of moles of CuO required $=\frac{1}{2}\left(14+\frac{17}{2}\right)=\frac{45}{4}=1125\times 10^{-2}$