Chemistry - Metallurgy Question with Solution | TestHub

(A) By electrolysing aq. NaCl

At anode : $\frac{2C{l}^{-}\text{buildrel}}{⟶C{l}_2\uparrow +2e^{-}}$

At cathode : $\frac{2H^{+}+2e^{-}\text{buildrel}}{⟶H_2\uparrow }$

(B)${\mathrm{Na}}_2\mathrm{O}+{\mathrm{H}}_2\stackrel{\Delta }{\to }[2\mathrm{NaOH}+\underset{\text{ vapours }}{{\mathrm{H}}_2\mathrm{O}]}2\mathrm{NaOH}+{\mathrm{H}}_2$

(C) NaCl cannot be decomposed to metallic sodium by heating.

(D)${\mathrm{Na}}^{+}{\mathrm{Cl}}^{-}$(s) $\stackrel{\Delta }{\to }\underset{\text{Fused state }}{\underbrace{{\mathrm{Na}}^{+}+{\mathrm{Cl}}^{-}}}$

At anode : $\frac{2C{l}^{-}\text{buildrel}}{⟶C{l}_2+2e^{-}}$

At cathode : $\frac{2Na+2e^{-}\text{buildrel}}{⟶2Na}$