' P ' is ore of Chromium. During formation of ' Q ' from ' P ' side-products ' X ' and ' Y ' ( g ) are produced. M o l ec u l a r ma ss ∘ f Y ( g ) M

Question

' P ' is ore of Chromium. During formation of ' Q ' from ' P ' side-products ' X ' and ' Y ' $(g)$ are produced.

$\frac{M o l ec u l a r ma ss \circ f X}{M o l ec u l a r ma ss \circ f Y ( g )}$ = Z. What is 'Z' ?

[Atomic mass : Na = 23, S = 16, Cr = 52, C = 12, O = 16, K = 39]

TestHub · Accepted Answer

4 FeCr 2 ​ O 4 ​ + 8 Na 2 ​ CO 3 ​ + 7 O 2 ​ → ​ 8 Na 2 ​ CrO 4 ​ + 2 Fe 2 ​ O 3 ​ ( X ) + 8 CO 2 ​ ↑ ​ ​ M Y ​ M X ​ ​ = 44 160 ​ = 3.63

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