Chemistry - Liquid Solution Question with Solution | TestHub

$\Delta {\mathrm{t}}_{\mathrm{f}}={\mathrm{K}}_{\mathrm{f}}\times \mathrm{m},\Delta {\mathrm{t}}_{\mathrm{b}}={\mathrm{K}}_{\mathrm{b}}\times \mathrm{m}$

$m=\frac{\Delta t_f}{K_f}$ and $m=\frac{\Delta t_b}{K_b}$

Therefore, $\frac{\Delta t_f}{K_f}=\frac{\Delta t_b}{K_b}$.

Given $K_f=1.86$ and $K_b=0.512$, and assuming $\Delta t_f=0.186$:

$$\frac{0.186}{1.86}=\frac{\Delta t_b}{0.512}$$

$$0.1=\frac{\Delta t_b}{0.512}$$

$$\Delta t_b=0.1\times 0.512$$

$$\Delta t_b=0.0512°C$$