Chemistry - Liquid Solution Question with Solution | TestHub

Given molecular mass of sucrose$=342$
Moles of sucrose$=\frac{100}{342}=0.292$mole
Moles of water$\mathrm{N}=\frac{1000}{18}=55.5$moles and
Vapour pressure of pure water${\mathrm{P}}^0=\mathrm{23.8 }\mathrm{m}\mathrm{m}\mathrm{}\mathrm{H}\mathrm{g}$
According to Raoult’s law$\frac{\mathrm{\Delta }\mathrm{P}}{{\mathrm{P}}^0}=\frac{\mathrm{n}}{\mathrm{n}+\mathrm{N}}\Rightarrow \frac{\mathrm{\Delta }\mathrm{P}}{23.8}=\frac{0.292}{0.292+55.5}$
$\mathrm{\Delta }\mathrm{P}=\frac{23.8\times 0.292}{55.792}=\mathrm{0.125 }\mathrm{}\mathrm{m}\mathrm{m}\mathrm{}\mathrm{H}\mathrm{g}$.