Chemistry - Liquid Solution Question with Solution | TestHub

Given:

Mass of hemoglobin $w=21.5mg=0.0215g$, Volume $V=1.5mL=0.0015L$

$\pi =3.8torr=\frac{3.8}{760}atm$, $T=300K$

Using the osmotic pressure formula:

$$\pi =\frac{wRT}{MV}$$

We can rearrange to solve for $M$:

$$M=\frac{wRT}{\pi V}=\frac{0.0215\times 0.08\times 300}{(3.8/760)\times 0.0015}$$

$$M\approx 6.88\times 10^{4}g/mol$$

Therefore, the molar mass of hemoglobin is $6.88\times 10^{4}g/mol$ (Option C).