A solution has a 1 : 4 mole ratio of pentane to hexane. The vapour pressure of the pure hydrocarbons at 2 0 ∘ C are 440 mm Hg for pentane and 120 mm Hg for hexane. The mole fraction of pentane in the

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A solution has a 1 : 4 mole ratio of pentane to hexane. The vapour pressure of the pure hydrocarbons at 2 0 ∘ C are 440 mm Hg for pentane and 120 mm Hg for hexane. The mole fraction of pentane in the vapour phase would be:

TestHub · Accepted Answer

P = 440 × 5 1 ​ + 120 × 5 4 ​ = 184 mm H g ( X p e n t an e ​ ) v a p o u r p ha se ​ 184 = 440 × 5 1 ​ ​ = 0.478 mm H g

Chemistry - Liquid Solution Question with Solution | TestHub

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