The vapour pressure of pure water at 6 0 ∘ C is 150 torr. The vapour pressure of water over a solution at 6 0 ∘ C containing equal numbers of moles of water and ethylene glycol (a non volatile solute)

Question

The vapour pressure of pure water at 6 0 ∘ C is 150 torr. The vapour pressure of water over a solution at 6 0 ∘ C containing equal numbers of moles of water and ethylene glycol (a non volatile solute) is 50 torr. Which of the following is correct.

TestHub · Accepted Answer

P ∘ solvent ​ = 150 torr P s ​ = 50 torr R.L.V.P. = P ∘ solvent ​ P ∘ solvent ​ − P s ​ ​ R.L.V.P. = 150 150 − 50 ​ R.L.V.P. = 150 100 ​ = 3 2 ​ Ans due to H -bonding on reaction between water and Ethylene glycol. It shows (-)ive deviation 50Δ H mix ​ < 0 .

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JEE Advanced 2027 (Class 12+)