Arrange the following aqueous solutions in order of increasing freezing points (that is lowest first)
(I) $0.10 m Ba_{3} (PO_{4})_{2}$
(II) $0.10 m Na_{2} SO_{4}$
(III) $0.10 m C_{2} H_{5} OH$
(IV) 0.10 m KCl
(V) $0.10 m Li_{3} PO_{4}$

Question

Arrange the following aqueous solutions in order of increasing freezing points (that is lowest first)

(I) $0.10 m Ba_{3} (PO_{4})_{2}$

(II) $0.10 m Na_{2} SO_{4}$

(III) $0.10 m C_{2} H_{5} OH$

(IV) 0.10 m KCl

(V) $0.10 m Li_{3} PO_{4}$

TestHub · Accepted Answer

Δ T 1 ​ = K 1 ​ × m × i if i ↑= Δ T f ​ ↑ and freezing point decreases Ba 3 ​ ( PO 4 ​ ) 2 ​ ⇒ i = 5 Na 2 ​ SO 4 ​ ⇒ i = 3 C 2 ​ H 5 ​ OH ⇒ i = 1 KCl ⇒ i = 2 Li 3 ​ PO 4 ​ ⇒ i = 4

Chemistry - Liquid Solution Question with Solution | TestHub

Options:

Doubts & Discussion