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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionColligative PropertiesMedium2 minQB

ChemistryMediumnumerical

Find the mass (in gram) of glucose that should be dissolved in 90 g of water in order to produce the same lowering of vapour pressure as produced by dissolving 13.35 gram of $AlCl_{3}$ in 45 g of water.

(Given : atomic mass of Al = 27, Cl= 35.5)

Answer:

144.00

Solution:

$\frac{P _{0} - P _{S}}{P _{0}} = X_{solute}$

$X_{g l u c o s e} = X_{A lC l_{3}}$

$\frac{\frac{W_{g l u}}{180}}{\frac{W_{g l u}}{180} + \frac{90}{18}} = \frac{4 \times \frac{13.35}{133.5}}{(4 \times \frac{13.35}{133.5}) + \frac{45}{18}}$

$\frac{W _{g l u}}{W _{g l u} + 900} = \frac{0.4}{2.9}$

$W_{g l u} = 144 g m$

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Colligative Properties

⏱ 2mℹ️ Source: QB

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