The correct option for the value of vapour pressure of a solution at $45 º C$ with benzene to octane in molar ratio $3 : 2$ is:
[At $45 ° C$ vapour pressure of benzene is $280 mm Hg$ and that of octane is $420 mm Hg .$ Assume Ideal gas]
NEET 2021

Question

The correct option for the value of vapour pressure of a solution at $45 º C$ with benzene to octane in molar ratio $3 : 2$ is:

[At $45 ° C$ vapour pressure of benzene is $280 mm Hg$ and that of octane is $420 mm Hg .$ Assume Ideal gas]

NEET 2021

TestHub · Accepted Answer

Given: P B ° = 280 mm of Hg , P o ° = 420 mm of Hg X B = 3 5 and X o = 2 5 We know that according to Raoult's Law P T = X B P B ° + X o P o ° = 3 5 × 280 + 2 5 × 420 = 336 mm of Hg

Chemistry - Liquid Solution Question with Solution | TestHub

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