At 300 K, two solutions of glucose in water of concentration 0.01 M and 0.001 M are separated by semipermeable membrane. Pressure needs to be applied on which solution, to prevent osmosis? Calculate t

Question

At 300 K, two solutions of glucose in water of concentration 0.01 M and 0.001 M are separated by semipermeable membrane. Pressure needs to be applied on which solution, to prevent osmosis? Calculate the magnitude of this applied pressure, in atm.

TestHub · Accepted Answer

For preventing osmosis, pressure equal to the difference in osmotic pressure is applied on the more concentrated solution (0.01 M glucose).

The osmotic pressure $π$ is given by the formula $π = CRT$ .

The difference in osmotic pressure $Δ π$ is:

$Δ π = (C_{1} - C_{2}) RT$

$= (0.01 - 0.001) \times 0.0821 \times 300$

$= 0.009 \times 24.63$

$= 0.221 a t m$

Therefore, the applied pressure is $0.22 a t m$ on the 0.01 M glucose solution

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