0.05 moles of N₂ gas dissolves completely in 900 gm water at 2 7 ∘ C , as shown in the following figure. The available space between piston and liquid solution is 16.42 L. Find the number of moles of

Question

0.05 moles of N₂ gas dissolves completely in 900 gm water at $2 7^{\circ} C$ , as shown in the following figure.

The available space between piston and liquid solution is 16.42 L. Find the number of moles of N₂ in the gaseous phase.

(Henry's Law constant for N₂ gas = $7.2 \times 1 0^{4} a t m$ ). ( $R = 0.0821 a t m \cdot L \cdot m o l^{- 1} \cdot K^{- 1}$ )

TestHub · Accepted Answer

P N 2 ​ ​ = 7.2 × 1 0 4 × 50 0.05 ​ P N 2 ​ ​ × 16.42 = n × 0.82 × 300 Moles = 48

Chemistry - Liquid Solution Question with Solution | TestHub