Two liquids X and Y form an ideal solution. At 300 K, vapour pressure of the solutions containing 1 mol of X and 3 mol of Y is 550 mmHg. At the same temperature, if 1 mol of Y is further added to this

Question

Two liquids X and Y form an ideal solution. At 300 K, vapour pressure of the solutions containing 1 mol of X and 3 mol of Y is 550 mmHg. At the same temperature, if 1 mol of Y is further added to this solution, vapour pressure of the solution increases by 10 mmHg. Vapour pressure [ i n m m H g ] of X and Y in their pure states will be, respectively:

TestHub · Accepted Answer

P T = P X o X X + P Y o X Y X X = mol fraction of X X Y = mol fraction of Y 550 = P X o 1 1 + 3 + P Y o 3 1 + 3 = P X o 4 + 3 P Y o 4 560 × 4 = P X o + 3 P Y o …(1) 560 × 5 = P x o + 4 P y o .....(2) By Solving (i) and (ii) We get, P X o = 400 m m H g P Y o = 600 m m H g

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