Chemistry - Liquid Solution Question with Solution | TestHub

Explain Question : Which is isotonic with $15\%\frac{\mathrm{W}}{\mathrm{W}}$ glucose solution.

Concept :

Isotonic solution

Solution : for glucose $\mathrm{i}=1$

$\pi =\mathrm{i}$ CRT

${\pi }_{\text{glucose }}=1\times \frac{\%\mathrm{w}/\mathrm{w}\times 10\times \mathrm{d}}{{\mathrm{M}}_{\omega }}\mathrm{RT}$

$=1\times \frac{15\times 10\times 1.2}{180}\times RT$

${\pi }_{\text{glucos }\mathrm{e}}=\mathrm{RT}$

isotonic solution i.e same osmotic pressure

$0.5\mathrm{M}\Rightarrow {\pi }_{\mathrm{NaCl}}=\mathrm{iCRT}=2\times 0.5\mathrm{RT}=\mathrm{RT}$ $1\mathrm{N}\Rightarrow {\pi }_{{\mathrm{CaCl}}_2}=\mathrm{iCRT}=3\times \frac{1}{2}\mathrm{RT}=1.5\mathrm{RT}$ $1\mathrm{M}\Rightarrow {\pi }_{{\mathrm{CaCl}}_2}=\mathrm{iCRT}=3\times 1\times \mathrm{RT}=3\mathrm{RT}$ $0.5\Rightarrow {\pi }_{\text{urea }}=\mathrm{iCRT}=1\times 0.5\mathrm{RT}=0.5\mathrm{RT}$ Final Answer option (C)