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ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minQB

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The Van’t Hoff’s factor ( $i$ ) for a dilute aqueous solution of Na₂SO₄ is

Answer:

Solution:

$Na_{2} SO_{4} ⇌ 2 Na^{+} + SO_{4}^{2 -}$

$1$ 0 0

$(1 - α) 2 α α$

Where ' $α$ ' is the degree of dissociation.

Therefore, $i = 1 - α + 2 α + α = 1 + 2 α$ .

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: QB

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