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ChemistryLiquid SolutionMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

A solution containing $10 g$ of a non-volatile, higher nonelectrolyte and $400 g$ of water boils at $100 {.256}^{o} C$ at $1 atm$ . The molecular weight of the solute $(in g/mol)$ is
Given: ( $K_{b}$ for water $0.512 {}^{ο}C / m$ )

Answer:

50.00

Solution:

$Δ T_{b} = i \times K_{b} \times m$
$0.256 = 1 \times 0.512 \times (\frac{\frac{10.0}{M}}{0.4})$
$M = \frac{0.512 \times 10.0}{0.4 \times 0.256}$
$M = 50 g/mol$

Stream:NTA_ABHYASSubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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