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ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minQB

ChemistryMediumsingle choice

For the given electrolyte $X_{m} Y_{n}$ , the degree of dissociation ' $α$ ' is given by (' $i$ ' is the Vant Hoff factor)

Answer:

Solution:

$X_{m} Y_{n} ⇌ mX^{n +} + nY^{m +}$

$(1 - α)$ $m α$ $n α$

Therefore, $i = \frac{1 - α + m α + n α}{1}$

Thus, $α = \frac{i - 1}{m + n - 1} = \frac{1 - i}{1 - m - n}$ .

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: QB

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