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ChemistryLiquid SolutionRaoult's LawEasy2 minPYQ_2020

ChemistryEasysingle choice

Total vapour pressure of mixture of 1 mol $A (P_{A}^{o} = 150$ torr) and 2 mol $B (P_{B}^{o} = 240$ torr) is 200 torr. In this case

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Answer:

Solution:

$X_{A} = \frac{1}{3}$
$X_{B} = \frac{2}{3}$
$P = P_{A}^{o} X_{A} + P_{B}^{o} X_{B}$
$= 150 \times \frac{1}{3} + 240 \times \frac{2}{3} = 50 + 160 = 210$ mm
$P_{o b s .} < P_{c a l c u l a t e d}$
So there is negative deviation from Raoult's law.
Hint : In –ve deviation observed pressure is less than expected or calculated pressure.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law

⏱ 2mℹ️ Source: PYQ_2020

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