At 9 0 ∘ C , the vapour pressure of toluene is 400 mm and that of xylene is 150 mm . The composition of liquid mixture that will boil at 9 0 ∘ C when the pressure of mixture is 0.5 atm , is -

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Total pressure P t o t a l ​ = P t o l u e n e ​ + P x y l e n e ​ = X t o l u e n e ​ P t o l u e n e ∘ ​ + X x y l e n e ​ P x y l e n e ∘ ​ . Given P t o t a l ​ = 0.5 a t m = 380 mm . 380 = X t o l u e n e ​ ( 400 ) + ( 1 − X t o l u e n e ​ ) ( 150 ) . Solving for X t o l u e n e ​ gives X t o l u e n e ​ = 0.92 . Thus, X x y l e n e ​ = 1 − 0.92 = 0.08 .

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