A solution of non volatile solute has boiling point elevation 0.70 K if K b for the solvent is 2.44 K kg mol − 1 . What is the molality of the solution?

Question

A solution of non volatile solute has boiling point elevation 0.70 K if K b ​ for the solvent is 2.44 K kg mol − 1 . What is the molality of the solution?

TestHub · Accepted Answer

The elevation in boiling point is given by the formula:

$Δ T_{b} = K_{b} \times m$

where $Δ T_{b}$ is the boiling point elevation, $K_{b}$ is the ebullioscopic constant, and $m$ is the molality of the solution.

Given:
$Δ T_{b} = 0.70$ K
$K_{b} = 2.44$ K kg mol $^{- 1}$

Substituting the given values into the formula:

$0.70 = 2.44 \times m$

$m = \frac{0.70}{2.44}$

$m \approx 0.286$ m

Answer: $0.286$ m

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