Calculate the cryoscopic constant of solvent when 2.5 gram solute is dissolved in 35 gram solvent lowers its freezing point by 3 K . (molar mass of solute is 117 g mol − 1 )

Question

TestHub · Accepted Answer

The depression in freezing point is given by the formula:

$Δ T_{f} = K_{f} \times m$

where $m$ is the molality of the solution, which can be expressed as:

$m = \frac{w _{2} \times 1000}{M _{2} \times w _{1}}$

Substituting the given values:

$3 = K_{f} \times \frac{2.5 \times 1000}{117 \times 35}$

$K_{f} = \frac{3 \times 117 \times 35}{2500}$

$K_{f} = \frac{12285}{2500} = 4.914 K kg mo l^{- 1}$

Answer: $4.91 K kg mol^{- 1}$

Chemistry - Liquid Solution Question with Solution | TestHub

Options:

Doubts & Discussion