Which of the following aqueous solutions exhibits maximum freezing point depression assuming complete dissociation?

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The depression in freezing point is given by $Δ T_{f} = i \times K_{f} \times m$ .

Since $K_{f}$ is constant for aqueous solutions, $Δ T_{f} \propto i \times m$ .

For $0.1$ m $Li_{2} SO_{4}$ , $i = 3$ , $i \times m = 3 \times 0.1 = 0.3$

For $0.5$ m KCl, $i = 2$ , $i \times m = 2 \times 0.5 = 1.0$

For $0.05$ m $Al_{2} (SO_{4})_{3}$ , $i = 5$ , $i \times m = 5 \times 0.05 = 0.25$

For $0.2$ m $BaCl_{2}$ , $i = 3$ , $i \times m = 3 \times 0.2 = 0.6$

The maximum value of $i \times m$ is $1.0$ for $0.5$ m KCl, which will exhibit the maximum freezing point depression.

Answer: $0.5$ m KCl.

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