Chemistry - Liquid Solution Question with Solution | TestHub

Given, number of molecules of urea $=6.02\times 10^{20}$ $\begin{array}{rl}& \therefore \text{ Number of moles }=\frac{6.02\times 10^{20}}{N_A}\\ & =\frac{6.02\times 10^{20}}{6.02\times 10^{23}}=1\times 10^{-3}\mathrm{mol}\end{array}$ Volume of the solution $=100\mathrm{mL}=\frac{100}{1000}\mathrm{L}=0.1\mathrm{L}$ Concentration of urea solution $\begin{array}{rl}\left(\text{ in }\mathrm{mol}{\mathrm{L}}^{-1}\right)& =\frac{1\times 10^{-3}}{0.1}\mathrm{mol}{\mathrm{L}}^{-1}\\ & =1\times 10^{-2}\mathrm{mol}{\mathrm{L}}^{-1}=0.01\mathrm{mol}{\mathrm{L}}^{-1}\end{array}$