Chemistry - Liquid Solution Question with Solution | TestHub

Let the mass of the solution be $100$ g.

Mass of glucose (solute) = $6$ g

Mass of water (solvent) = $100-6=94$ g = $0.094$ kg

Molar mass of glucose = $180$ g/mol

Moles of glucose = $\frac{6}{180}=\frac{1}{30}$ mol

Molality ($m$) = $\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}$

$m=\frac{1/30}{0.094}=\frac{1}{2.82}\approx 0.35$ m

Answer: $0.35$ m