The partial pressure of a gas at 2 5 ∘ C is 0.18 atm, calculate the concentration of the gas dissolved at the same temperature, If K H is 0.15 mol dm − 3 atm − 1

Question

The partial pressure of a gas at 2 5 ∘ C is 0.18 atm, calculate the concentration of the gas dissolved at the same temperature, If K H ​ is 0.15 mol dm − 3 atm − 1

TestHub · Accepted Answer

According to Henry's law, the concentration of a dissolved gas is directly proportional to its partial pressure.

$C = K_{H} \times P$

Given:
$P = 0.18 atm$
$K_{H} = 0.15 mol dm^{- 3} atm^{- 1}$

Substituting the values:
$C = 0.15 \times 0.18$

$C = 0.027 mol dm^{- 3}$

Since $1 mol dm^{- 3} = 1 M$ , the concentration is $0.027 M$ .

Answer: $0.027$ M

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