Chemistry - Liquid Solution Question with Solution | TestHub

Molality $=\frac{\text{ moles of solute }\times 1000}{\text{ weight of solvent (in g) }}$ Or $=\frac{\text{ weight of solute }\times 1000}{\text{ mol. wt of solute }\times \text{ weight of solvent (in g) }}$ $$=\frac{450\times 10^{-3}\times 1000}{180\times 100}$$ $[\because$ Mol. mass of glucose $=180]$ $=0.025\mathrm{m}$