Chemistry - Liquid Solution Question with Solution | TestHub

According to Henry's law, the solubility of a gas in a liquid is directly proportional to its partial pressure.

$S=K_{H}P$

Given the solubility $S_1=6.85\times 10^{-4}$ ${\text{mol L}}^{-1}$ at partial pressure $P_1=1$ $\text{bar}$.

The solubility $S_2$ at partial pressure $P_2=0.50$ $\text{bar}$ can be calculated as:

$\frac{S_1}{P_1}=\frac{S_2}{P_2}$

$S_2=S_1\times \frac{P_2}{P_1}$

$S_2=6.85\times 10^{-4}\times \frac{0.50}{1}$

$S_2=3.425\times 10^{-4}$ ${\text{mol L}}^{-1}$

Answer: $3.425\times 10^{-4}{\text{mol L}}^{-1}$