Chemistry - Liquid Solution Question with Solution | TestHub

Vapour pressure of pure solvent, $P_1^0=32\text{ mm Hg}$

Vapour pressure of solution, $P_1=30\text{ mm Hg}$

Relative lowering of vapour pressure is given by:

$\frac{P_1^0-P_1}{P_1^0}$

Substituting the given values:

$\frac{32-30}{32}=\frac{2}{32}=\frac{1}{16}=0.0625$

Answer: 0.0625