Chemistry - Liquid Solution Question with Solution | TestHub

$\begin{array}{rl}& {\mathrm{K}}_{\mathrm{a}}=1\times 10^{-5},\mathrm{c}=0.1\mathrm{M}\\ {\mathrm{K}}_{\mathrm{a}}& ={\alpha }^2\mathrm{c}\\ \therefore \alpha & =\sqrt{\frac{{\mathrm{K}}_{\mathrm{a}}}{\mathrm{c}}}=\sqrt{\frac{1\times 10^{-5}}{0.1}}=\sqrt{1\times 10^{-4}}=0.01\end{array}$ $\begin{array}{rl}& \alpha =\frac{\text{ Percent dissociation }}{100}\\ & \text{ Percent dissociation }=\alpha \times 100\\ & =0.01\times 100=1.0\%\\ & \end{array}$