Calculate the amount of solute dissolved in 612 grams of water at 3 0 ∘ C if molar mass of solute is 342 g mol − 1 (Relative vapour pressure lowering is 0.025 and molar mass of water 18 g mol − 1 )

P A ∘ Δ P = x B ≃ n A n B 342 W B × 612 18 = 0.025 W B = 290.7

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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minPYQ_2022

ChemistryMediumsingle choice

Calculate the amount of solute dissolved in 612 grams of water at $3 0^{\circ} C$ if molar mass of solute is $342 g mol^{- 1}$ (Relative vapour pressure lowering is 0.025 and molar mass of water $18 g mol^{- 1}$ )

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Answer:

Solution:

$\frac{Δ P}{P _{A}^{\circ}} = x_{B} ≃ \frac{n _{B}}{n _{A}}$ $\frac{W _{B}}{342} \times \frac{18}{612} = 0.025$ $W_{B} = 290.7$

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2022

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