Chemistry - Liquid Solution Question with Solution | TestHub

$\Delta \text{P}=\text{5.1 torr}$; x is atomicity of sulphur.

$\frac{\Delta \text{P}}{{\text{P}}_{\text{A}}^{\circ }}=\frac{\text{5.1}}{\text{850}}={\text{X}}_{\text{B}}=\frac{\frac{2}{32\text{x}}}{\frac{2}{32\text{x}}+\frac{100}{76}}$

$\frac{\text{5.1}}{\text{850}}\cong \frac{2}{32\text{x}}\times \frac{76}{100}$

$\text{x}=\frac{2\times 76}{32\times 100}\times \frac{850}{\text{5.1}}=\text{7.92}\approx 8$