How much amount of NaCl should be added to 600 g of water ( $ρ = 1.00 g / m L$ ) to decrease the freezing point of water to $- {0.2}^{o} C$ ?

(The freezing point depression constant for water $= 2 K kg mo l^{- 1}$ )

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TestHub · Accepted Answer

Δ T f = 0.2 Δ T f = i K f m i = 2 for NaCl 0.2 = 2 × 2 × m m = w 58.5 × 1000 600 0.2 = 2 × 2 × w 58.5 × 1000 600 w = 0.2 × 58.5 × 600 4 × 600 = 1.2 × 58.5 40 = 1.76 g

Chemistry - Liquid Solution Question with Solution | TestHub

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