The value of Henry's law constant for some gases at 293 K is given below. Arrange the gases in the increasing order of their solubility.
He: 144.97 kbar, $H_{2}$ : 69.16 kbar,
$N_{2}$ : 76.48 kbar, $O_{2}$ : 34.86 kbar

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Higher the value of K H , lower is the solubility of gas in the liquid. The correct order of solubility of these gases is as follows H e 144.97 < N 2 76.48 < H 2 69.16 < O 2 34.86 K H = 144.97,76.48,69.16,34.86 k b a r

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