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ChemistryLiquid SolutionMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

1 g of non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1:5. The ratio of the elevation in their boiling point, $\frac{Δ T_{b} (A)}{Δ T_{b} (B)},$ is

Options:

Answer:

Solution:

$Δ T_{b} = K_{b} \times m \Rightarrow Δ T_{b} \propto K_{b}$

As $m_{A} = m_{B}$ (given)

So $\frac{Δ T_{b (A)}}{Δ T_{b (B)}} = \frac{K_{b (A)}}{K_{b (B)}}$

As $\frac{K_{b (A)}}{K_{b (B)}} = \frac{1}{5}$

So $\frac{Δ T_{b (A)}}{Δ T_{b (B)}} = \frac{1}{5}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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