When a gas is bubbled through water at 298 K, a very dilute solution of gas is obtained. Henry's law constant for the gas is 100 kbar. If gas exerts a pressure of 1 bar, the number of moles of ga

Question

When a gas is bubbled through water at 298 K, a very dilute solution of gas is obtained. Henry's law constant for the gas is 100 kbar. If gas exerts a pressure of 1 bar, the number of moles of gas dissolved in 1 litre of water is $x \times 10^{- 5}$ . Find the value of $x$ here?
Report your answer upto two decimal places.

TestHub · Accepted Answer

p = K H × x x = p K H = 1 100 × 1 0 3 = 1 × 1 0 - 5 Mole of fraction = Mole of gas Total moles Moles of H 2 O = 1000 18 = 55 .55 ∴ 1 L = 1000 g × 10 − 5 Mole fraction = x x + 55.55 55.55 > > > x So 1 0 - 5 = x 55.55 or x = 55.55 × 1 0 - 5

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