Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2020
ChemistryEasysingle choice

Dissolution of 1.5 g of non-volatile solute (Molecular weight = 60) in 250 g of a solvent reduces its freezing point by0.01oC. Find the molal depression constant of the solvent.

Options:

Answer:
D
Solution:

Depression in freezing point,

ΔTf=kf×m

Where,

m=Molality=Weight of solute×1000Molecualr weight of solute ×Weight of solvent

=1.5×100060×250

ΔTf=0.1oC molal-1

⇒ΔTf=kf×0.1

0.01=kf×0.1

∴  kf=0.010.1

=0.1

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties
⏱ 2mℹ️ Source: PYQ_2020

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