Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2020

ChemistryEasysingle choice

The vapour pressure of water at $20 ℃$ is 17.54 mm Hg. When 20 g of a non-ionic, substance is dissolved in 100 g of water, the vapour pressure is lowered by 0.30 mm Hg. What is the molecular mass of the substance?

Options:

Answer:

Solution:

$\frac{p ° - p_{s}}{p °} = X_{s o l u t e}$

or

$\frac{p ° - p_{s}}{P_{s}} = \frac{n}{N}$

$∴ \frac{0.3}{17.24} = \frac{\frac{20}{M}}{\frac{100}{18}} {M = m o l a r m a s s o f s o l u t e}$

$∴ M = \frac{20 \times 18 \times 17.24}{0.3 \times 100} = 206.88$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2020

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