A solution has an osmotic pressure of 'x' kPa at 300 K having 1 mole of solute in 10 ⋅ 5 m 3 of solution. If it's osmotic pressure is reduced to ( 10 1 ) th of it's initial value

Question

A solution has an osmotic pressure of 'x' kPa at 300 K having 1 mole of solute in 10 ⋅ 5 m 3 of solution. If it's osmotic pressure is reduced to ( 10 1 ​ ) th of it's initial value, what is the new volume of solution?

TestHub · Accepted Answer

(A) π = X kPa , V = 10.5 m 3 , π ′ = 10 X ​ kPa , V ′ = ? π = v n ​ RT ​ i. X = 10.5 1 ​ × 8.314 × 300 ; ii. 10 X ​ = V ′ 1 ​ × 8.314 × 300 By dividing equation (i) by (ii) X /10 X ​ 10 ​ = 1/ V ′ × 8.314 × 300 1 ​ 10.5 1 ​ × 8.314 × 300 ​ = 10.5 V ′ ​ ∴ V ′ = 105 m 3 ​

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