Chemistry - Liquid Solution Question with Solution | TestHub

$0.8\mathrm{m}$ Given, Volume $=1{\mathrm{dm}}^3=10^3{\mathrm{cm}}^3$ Density $=1.25\mathrm{g}/{\mathrm{cm}}^3$ Mass $=60\mathrm{g}$ We know that, molahty $(M)=\frac{\text{ Moles }}{\text{ Mass of solvents }}$ $\therefore$ Moles $=\frac{\text{ Given mass }}{\text{ Molar mass }}$ $=\frac{60\mathrm{g}}{60\mathrm{g}/\mathrm{mol}}$ $=1\mathrm{mol}$ Molality $(\mathrm{m})=\frac{\text{ Moles }}{\text{ Volume }\times \text{ Density }}$ $\mathrm{m}=\frac{1}{1000{\mathrm{cm}}^3\times 1.25\mathrm{g}/{\mathrm{cm}}^3}$ $=\frac{1}{1.25\mathrm{g}\times 10^3}$ $\Rightarrow \frac{1}{1.25\mathrm{kg}}$ $=0.8\mathrm{m}$