Chemistry - Liquid Solution Question with Solution | TestHub

Partial pressure of dry air $=$ total pressure $\times$ mole fraction of dry air $$\begin{array}{ll}\Rightarrow {\mathrm{p}}_{\text{dry air }}& ={\mathrm{p}}_{\text{total }}\times {\lambda }_{\text{dry air }}\\ \text{ Given, }{\lambda }_{\text{saturated air }}& =0.02\\ {\lambda }_{\text{dry air }}& =1-0.02=0.98\\ {\mathrm{p}}_{\text{total }}& =1.2\mathrm{atm}\\ \therefore {\mathrm{p}}_{\text{dry air }}& =1.2\mathrm{atm}\times 0.98=1.176\mathrm{atm}\end{array}$$