Chemistry - Liquid Solution Question with Solution | TestHub

According to van't Hoff equation
$\text{Osmotic pressure}\left(\text{π}\right)=\text{i CRT}=\frac{{\text{in}}_{\text{B}}\text{RT}}{\text{V}}$
i = 2.47; V = 2.5 L; R = 0.0821 L atm K^-1mol^-1
T = 27 + 273 = 300 K; π = 0.75 atm
${\text{n}}_{\text{B}}=\frac{\text{π}\text{V}}{\text{iRT}}$
$=\frac{\left(\text{0.75 atm}\right)\times \left(\text{2.5 L}\right)}{\left(\text{2.47}\right)\times \left({\text{0.0821 L atm K}}^{-1}{\text{mol}}^{-1}\right)\times \left(\text{300 K}\right)}=\text{0.0308 mol}$
Amount of CaCl₂dissolved = n_B× M_B
= (0.0308 mol) × (111 g mol^-1)
= 3.42 g