Chemistry - Liquid Solution Question with Solution | TestHub

$\frac{P_A^0-P_{solution}}{P_A^0}$$=0.0125={\chi }_B=\frac{n_B}{n_A+n_B}$; therefore, ${\chi }_A=0.9875=\frac{n_A}{n_A+n_B}$.

Thus, $\frac{n_B}{n_A}=\frac{1}{79}$.

$m=\frac{n_B}{Kg\left(solventof.wt\right)}=\frac{n_B}{n_A\times molarmass\circ fsolvent)\times 10^{-3}}$

$=\frac{1}{79\times 18\times 10^{-3}}\approx 0.70$