Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionRaoult's LawEasy2 minPYQ_2020
ChemistryEasysingle choice

At80∘C , the vapour pressure of pure liquid 'A' is 520 mm  Hg and that of pure liquid 'B' is 1000 mm  Hg. If a mixture solution of 'A' and 'B' boils at80∘Cand 1 atm pressure, the amount of 'A' in the mixture is:
( 1 atm =760 mm  Hg )

Options:

Answer:
D
Solution:

PT = PA∘XA+PB∘XB

Mixture solution boil at 1 atm = 760 mm Hg = total pressure of solution.

7 6 0 = 520X A + 1 0 00 1 - X A

⇒ 7 6 0 = 5 2 0 X A + 1 0 0 0 - 1 0 0 0 X A ⇒ 4 8 0 X A = 2 4 0 ​

X A =0.5,

mole percentage of A=50%

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law
⏱ 2mℹ️ Source: PYQ_2020

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