Elevation in boiling point for 1.5 molal solution of glucose in water is 4K . The depression in freezing point for 4.5 molal solution of glucose in water is 4K . The ratio of molal elevation constant

Question

Elevation in boiling point for 1.5 molal solution of glucose in water is 4K . The depression in freezing point for 4.5 molal solution of glucose in water is 4K . The ratio of molal elevation constant to molal depression constant $(K_{b} / K_{f})$ is $____$ .

Answer:

3

Solution:

$Δ T_{b} = iK_{b} m$

$Δ T_{f} = i K_{f} m$

$\frac{4}{4} = \frac{K _{b} 1.5}{K _{f} 4.5}$

$\frac{K _{b}}{K _{f}} = 3$

TestHub · Accepted Answer

Δ T b ​ = iK b ​ m ​ Δ T f ​ = i K f ​ m ​ ​ ​ 4 4 ​ = K f ​ 4.5 K b ​ 1.5 ​ K f ​ K b ​ ​ = 3

Chemistry - Liquid Solution Question with Solution | TestHub

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