Start Free Mock LoginAlready registered? Login here

Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionRaoult's LawEasy2 minPYQ_2020

ChemistryEasysingle choice

Total vapour pressure of mixture of
1 mol volatile component $A (P ° A = 100 m m H g)$ and $3 m o l$ of volatile component $B (P ° B = 60 m m H g)$ is $75 m m$ . For such case-

Options:

Answer:

Solution:

$P_{T}^{o} = P_{A}^{o} X_{A} + P_{B}^{o} X_{B}$
${P^{o}}_{T} = \frac{1}{4} \times 100 + \frac{3}{4} \times 60 = \frac{280}{4} = 70$
(According to Raoult’s law)

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...