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ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minPYQ_2011

ChemistryMediumsingle choice

$1.00 g$ of a non-electrolyte solute (molar mass $250 g mol^{- 1})$ was dissolved in $51.2 g$ of benzene. If the freezing point depression constant, $K_{f}$ of benzene is $5.12 K kg mol^{- 1}$ , the freezing point of benzene will be lowered by

Options:

Answer:

Solution:

$Δ T_{f} = K_{f} m = 5.12 \times \frac{1}{250} \times \frac{1000}{51.2} = 0.4 K$

Stream:BITSATSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2011

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