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ChemistryLiquid SolutionRaoult's LawHard2 minPYQ_2019
ChemistryHardsingle choice

LiquidMand liquidNform an ideal solution. The vapour pressures of pure liquidsMandNare450and700 mmHg,respectively, at the same temperature. Then correct statements is:
(xM=Mole fraction of 'M' in solution;
xN=Mole fraction of 'N'in solution;
yM=Mole fraction of 'M' in vapour phase;
yN=Mole fraction of 'N' in vapour phase;)

Options:

Answer:
A
Solution:

PMo  is given as=450 mm of Hg.

PNo  is given as=700 mm of Hg.

We know that PM=xM×P MO Raoult’s law.

PN=xN×P NO Raoult’s law.

From Dalton’s law PM=yM×PT

PN=yM×PT

So,

xM×P Mo=yM×PT  (i)

xM×PNo=yN×PT    (ii)

(i) (ii) xMxN×P  MoP  No = yMyN

xMxN=yMyN×750450

xMxN>yMyN

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law
2mℹ️ Source: PYQ_2019

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