For a liquid the vapour pressure is given by log 10 ⁡ P = - 400 T + 10 Vapour pressure of the liquid is 10 x mm Hg at 400 K . The value of x will be?

log 10 ⁡ P = - 400 T + 10 = - 400 400 + 10 = 9 P = 10 9 mm Hg x = 9 .

Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

For a liquid the vapour pressure is given by
$\log_{10} P = \frac{- 400}{T} + 10$
Vapour pressure of the liquid is $10^{x} mm Hg$ at $400 K$ . The value of $x$ will be?

Answer:

9.00

Solution:

$\log_{10} P = - \frac{400}{T} + 10 = - \frac{400}{400} + 10 = 9$
$P = 10^{9} mm Hg$
$x = 9$ .

Stream:NTA_ABHYASSubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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